Calcule os parâmetros h e g da rede do Ex. 14.8.1 Passo 1Iae, meus queridos! Td certinho?? Antes de tudo, vamos nos lembrar das equações das malhas do circuito. {[[V_1 (s) = 6 I_1 (s) + 4 I_2 (s)],[V_2 (s) = 4 I_1 (s) + 10 I_2 (s)]]) Primeiro vamos calcular os parâmetros h da rede. {[[V_1 (s) = h_11 I_1 (s) + h_12 V_2 (s)],[I_2 (s) = h_2 1 I_1 (s) + h_2 2 V_2 (s)]]) h_11 : h_11 = (V_1 (s))/(I_1 (s)) (|_V_2 (s) = 0 Pra chegar a essa razão, vamos manipular as equações de malhas. V_2 (s) = 4 I_1 (s) + 10 I_2 (s) = 0 *fazendo V_2 (s) = 0 I_2 (s) = - (4)/(10) I_1 (s) *substituindo em V_1 V_1 (s) = 6 I_1 (s) + 4 (- (4)/(10) I_1 (s)) V_1 (s) = (6 0)/(10) I_1 (s) - (16)/(10) I_1 (s) V_1 (s) = (44)/(10) I_1 (s) (V_1 (s))/(I_1 (s)) = h_11 = (44)/(10) h_12 : h_12 = (V_1 (s))/(V_2 (s)) (|_I_1 (s) = 0 (V_1 (s))/(V_2 (s)) = (6 I_1 (s) + 4 I_2 (s))/(4 I_1 (s) + 10 I_2 (s)) (|_I_1 (s) = 0 (V_1 (s))/(V_2 (s)) = (0 + 4 I_2 (s))/(0 + 10 I_2 (s)) (V_1 (s))/(V_2 (s)) = h_12 = (4)/(10) h_21 : h_2 1 = (I_2 (s))/(I_1 (s)) (|_V_2 (s) = 0 V_2 (s) = 4 I_1 (s) + 10 I_2 (s) = 0 10 I_2 (s) = - 4 I_1 (s) (I_2 (s))/(I_1 (s)) = h_21 = - (4)/(10) h_22 : h_22 = (V_2 (s))/(I_2 (s)) (|_I_1 (s) = 0 V_2 (s) = 4 I_1 (s) + 10 I_2 (s) (|_I_1 (s) = 0 V_2 (s) = 0 + 10 I_2 (s) (V_2 (s))/(I_2 (s)) = h_22 = (1)/(10) Passo 2Por fim, calculando os parâmetros g da rede. {[[I_1 (s) = g_1 1 V_1 (s) + g_1 2 I_2 (s)],[V_2 (s) = g_2 1 V_1 (s) + g_2 2 I_2 (s)]]) g_11 : g_11 = (I_1 (s))/(V_1 (s)) (|_I_2 (s) = 0 V_1 (s) = 6 I_1 (s) + 4 I_2 (s) (|_I_2 (s) = 0 V_1 (s) = 6 I_1 (s) + 0 (I_1 (s))/(V_1 (s)) = g_11 = (1)/(6) g_12 : g_1 2 = (I_1 (s))/(I_2 (s)) (|_V_1 (s) = 0 V_1 (s) = 6 I_1 (s) + 4 I_2 (s) (|_V_1 (s) = 0 0 = 6 I_1 (s) + 4 I_2 (s) 6 I_1 (s) = - 4 I_2 (s) (I_1 (s))/(I_2 (s)) = g_12 = - (4)/(6) g_21 : g_21 = (V_2 (s))/(V_1 (s)) (|_I_2 (s) = 0 g_21 = (V_2 (s))/(V_1 (s)) = (4 I_1 (s) + 10 I_2 (s))/(6 I_1 (s) + 4 I_2 (s)) (|_I_2 (s) = 0 g_21 = (V_2 (s))/(V_1 (s)) = (4 I_1 (s) + 0)/(6 I_1 (s) + 0) (V_2 (s))/(V_1 (s)) = g_21 = (4)/(6) g_22 : g_22 = (V_2 (s))/(I_2 (s)) (|_V_1 (s) = 0 0 = 6 I_1 (s) + 4 I_2 (s) I_1 (s) = - (4)/(6) I_2 (s) *substituindo em V_2 V_2 (s) = 4 (- (4)/(6) I_2 (s)) + 10 I_2 (s) V_2 (s) = - (16)/(6) I_2 (s) + (6 0)/(6) I_2 (s) V_2 (s) = (44)/(6) I_2 (s) (V_2 (s))/(I_2 (s)) = g_22 = (44)/(6) Um pouco trabalhoso só, mas bem simples de resolver, oq vc achou? RespostaParâmetros h: h_11 = (44)/(10) , h_12 = (4)/(10) , h_21 = - (4)/(10) , h_22 = (1)/(10) . Parâmetros g: g_11 = (1)/(6) , g_12 = - (4)/(6) , g_21 = (4)/(6) , g_22 = (44)/(6) . MOSTRAR SOLUÇÃO COMPLETA