Responde Aí
Acesse com GoogleAcesse com AppleAcesse com Facebook

Enunciado

Termodinâmica - Moran e Shapiro - Princípios de Termodinâmica para Engenharia- Ed: 7º - Capítulo 12.Problemas - Ex. 14

Para um dos sistemas binários listados na tabela, com base na Eq. (10.5) e na equação NRTL, prepare um diagrama P - x - y para t = 60 ∘ C .

Passo 1

Coeficientes Antoine:

I- propanol A 1 : = 16.1154           B 1 : = 3483.67 ⋅ K         C l : = 205.807 ⋅ K  

Água A 2 : = 16.3872         B 2 : = 3885.70 ⋅ K           C 2 : = 230.170 ⋅ K  

P s a t 1 ⁡ ( T ) : = e x p ⁡ A l - B 1 ( T - 273.15 ⋅ K ) + C l ⋅ k P a

P s a t 2 ⁡ ( T ) : = e x p ⁡ A 2 - B 2 ( T - 273.15 ⋅ K ) + C 2 ⋅ k P a

Parâmetros da equação NRTL

b 12 : = 500 ⋅ 40 - c a l m o l b 21 : = 1636.57 ⋅ c a l m o l α : = 0.5081

τ 12 ( T ) : = b 12 R ⋅ T τ 21 ( T ) : = b 21 R ⋅ T

G 12 ( T ) : = e x p ⁡ ( - α ) ⋅ 12 ( T ) G 21 ( T ) : = e x p ⁡ ( - α ) ⋅ 21 ( T )

Passo 2

γ 1 ( x 1 , x 2 , T ) : = e x p ⁡ x 2 2 ⋅ τ 21 ( T ) ⋅ G 21 ( T ) x 1 + x 2 ⋅ G 21 ( T ) 2   + G 12 ( T ) ⋅ τ 12 ( T ) ( x 2 + x 1 ) ⋅ G 12 ( T ) ) 2  

γ 2 ( x 1 , x 2 , T ) : = e x p ⁡ x 1 2 ⋅ τ 12 ( T ) ⋅ G 12 ( T ) x 2 + x 1 ⋅ G 12 ( T ) 2   + G 21 ( T ) ⋅ τ 21 ( T ) ( x 1 + x 2 ⋅ G 21 ( T ) ) 2  

Passo 3

P - x ,   y   d i a g r a m a   e m   T : = ( 60 + 273.15 ) ⋅ K

Achado: P : = 70 ⋅ k P a

Dados P = x 1 ⋅ γ 1 ( x 1,1 - x 1 , T ) ⋅ P s a t 1 ( T ) …

+ ( 1 - x 1 ) ⋅ γ 2 ( × 1,1 - x 1 , T ) ⋅ P s a t 2 ⁡ ( T )

P e q ⁡ ( x 1 ) : = F i n d ( P )

y e q ⁡ ( x 1 ) : = x 1 ⋅ γ 1 ( x 1,1 - x 1 , T ) ⋅ P s a t 1 ( T ) P e q ⁡ ( x 1 )

x : = 0,0.05 … 1.0

Resposta

P , x , y   D i a g r a m a   e m   T = 333.15 K

Ver Outros Exercícios desse livro