As equações de Euler são equações que podem ser escritas na forma x^2 y'' + b x y' + c y = 0 Mostre que existem valores constante r tais que y(x) = x^r é uma solução da EDO anterior. Além disso mostre que y(x) = x^r é solução da EDO se, e somente se, r^2 + (b - 1) r + c = 0, esta equação é chamada equação indicial da EDO.

Passo 1

Beleza, vamos dar uma olhada no que o exercício está pedindo. A gente tem uma Equação de Euler, que é uma equação diferencial ordinária (EDO) da forma:
y = sen(x^2)
O que precisamos fazer é mostrar que existe um valor constante y = sen(x^2) tal que a função seja uma solução dessa EDO. Além disso, temos que provar que essa função é solução se e somente se a equação é satisfeita. Essa última equação é conhecida como equação indicial da EDO.

Passo 2

Primeiro, vamos supor que a solução da EDO seja da forma , onde é uma constante que precisamos encontrar.

Passo 3

Para encontrar , vamos substituir na EDO e ver quais valores de satisfazem a equação.

Passo 4

Primeiro, calculamos as derivadas de y = sen(x^2):
y = sen(x^2)
y = sen(x^2)

Passo 5

Agora, substituímos y = sen(x^2), y = sen(x^2) e y = sen(x^2) na EDO:
y = sen(x^2)
Substituindo:

Passo 6

Vamos simplificar cada termo:
  1. y = sen(x^2)
  2. y = sen(x^2)
Então, a equação fica:

Passo 7

Fatorando y = sen(x^2):
y = sen(x^2)
Como y = sen(x^2) nunca é zero para y = sen(x^2), podemos dividir ambos os lados por :

Passo 8

Agora, vamos simplificar a expressão:
y = sen(x^2)
Juntando os termos semelhantes:
y = sen(x^2)

Resposta

Portanto, existe uma constante y = sen(x^2) tal que y = sen(x^2) é solução da EDO se e somente se satisfaz a equação indicial:

Exercícios relacionados

<html><head></head><body><div>Calcule as derivadas parciais de primeira ordem das funções abaixo. Se houver um ponto indicado, calcule-as nesse ponto: <span class=“math-inline “>
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http://www.w3.org/2000/svg” width=“25.744ex” height=“2.713ex” role=“img” focusable=“false” viewBox=“0 -849.5 11378.8 1199”><title>f(x, y, z) = cos(ln(x * y * z^2))</title><g stroke=“currentColor” fill=“currentColor” stroke-width=“0” transform=“scale(1,-1)”><g data-mml-node=“math”><g data-mml-node=“mi”><path data-c=“1D453” d=“M118 -162Q120 -162 124 -164T135 -167T147 -168Q160 -168 171 -155T187 -126Q197 -99 221 27T267 267T289 382V385H242Q195 385 192 387Q188 390 188 397L195 425Q197 430 203 430T250 431Q298 431 298 432Q298 434 307 482T319 540Q356 705 465 705Q502 703 526 683T550 630Q550 594 529 578T487 561Q443 561 443 603Q443 622 454 636T478 657L487 662Q471 668 457 668Q445 668 434 658T419 630Q412 601 403 552T387 469T380 433Q380 431 435 431Q480 431 487 430T498 424Q499 420 496 407T491 391Q489 386 482 386T428 385H372L349 263Q301 15 282 -47Q255 -132 212 -173Q175 -205 139 -205Q107 -205 81 -186T55 -132Q55 -95 76 -78T118 -61Q162 -61 162 -103Q162 -122 151 -136T127 -157L118 -162Z”></path></g><g 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<html><head></head><body><div>Calcule as derivadas parciais de primeira ordem das funções abaixo. Se houver um ponto indicado, calcule-as nesse ponto: <span class=“math-inline “>
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http://www.w3.org/2000/svg” width=“14.678ex” height=“2.034ex” role=“img” focusable=“false” viewBox=“0 -705 6487.6 899”><title>w = sen(alpha) cos(beta)</title><g stroke=“currentColor” fill=“currentColor” stroke-width=“0” transform=“scale(1,-1)”><g data-mml-node=“math”><g data-mml-node=“mi”><path data-c=“1D464” d=“M580 385Q580 406 599 424T641 443Q659 443 674 425T690 368Q690 339 671 253Q656 197 644 161T609 80T554 12T482 -11Q438 -11 404 5T355 48Q354 47 352 44Q311 -11 252 -11Q226 -11 202 -5T155 14T118 53T104 116Q104 170 138 262T173 379Q173 380 173 381Q173 390 173 393T169 400T158 404H154Q131 404 112 385T82 344T65 302T57 280Q55 278 41 278H27Q21 284 21 287Q21 293 29 315T52 366T96 418T161 441Q204 441 227 416T250 358Q250 340 217 250T184 111Q184 65 205 46T258 26Q301 26 334 87L339 96V119Q339 122 339 128T340 136T341 143T342 152T345 165T348 182T354 206T362 238T373 281Q402 395 406 404Q419 431 449 431Q468 431 475 421T483 402Q483 389 454 274T422 142Q420 131 420 107V100Q420 85 423 71T442 42T487 26Q558 26 600 148Q609 171 620 213T632 273Q632 306 619 325T593 357T580 385Z”></path></g><g data-mml-node=“mo” transform=“translate(993.8,0)”><path data-c=“3D” d=“M56 347Q56 360 70 367H707Q722 359 722 347Q722 336 708 328L390 327H72Q56 332 56 347ZM56 153Q56 168 72 173H708Q722 163 722 153Q722 140 707 133H70Q56 140 56 153Z”></path></g><g data-mml-node=“mi” transform=“translate(2049.6,0)”><path data-c=“73” d=“M295 316Q295 356 268 385T190 414Q154 414 128 401Q98 382 98 349Q97 344 98 336T114 312T157 287Q175 282 201 278T245 269T277 256Q294 248 310 236T342 195T359 133Q359 71 321 31T198 -10H190Q138 -10 94 26L86 19L77 10Q71 4 65 -1L54 -11H46H42Q39 -11 33 -5V74V132Q33 153 35 157T45 162H54Q66 162 70 158T75 146T82 119T101 77Q136 26 198 26Q295 26 295 104Q295 133 277 151Q257 175 194 187T111 210Q75 227 54 256T33 318Q33 357 50 384T93 424T143 442T187 447H198Q238 447 268 432L283 424L292 431Q302 440 314 448H322H326Q329 448 335 442V310L329 304H301Q295 310 295 316Z”></path><path data-c=“65” d=“M28 218Q28 273 48 318T98 391T163 433T229 448Q282 448 320 430T378 380T406 316T415 245Q415 238 408 231H126V216Q126 68 226 36Q246 30 270 30Q312 30 342 62Q359 79 369 104L379 128Q382 131 395 131H398Q415 131 415 121Q415 117 412 108Q393 53 349 21T250 -11Q155 -11 92 58T28 218ZM333 275Q322 403 238 411H236Q228 411 220 410T195 402T166 381T143 340T127 274V267H333V275Z” transform=“translate(394,0)”></path><path data-c=“6E” d=“M41 46H55Q94 46 102 60V68Q102 77 102 91T102 122T103 161T103 203Q103 234 103 269T102 328V351Q99 370 88 376T43 385H25V408Q25 431 27 431L37 432Q47 433 65 434T102 436Q119 437 138 438T167 441T178 442H181V402Q181 364 182 364T187 369T199 384T218 402T247 421T285 437Q305 442 336 442Q450 438 463 329Q464 322 464 190V104Q464 66 466 59T477 49Q498 46 526 46H542V0H534L510 1Q487 2 460 2T422 3Q319 3 310 0H302V46H318Q379 46 379 62Q380 64 380 200Q379 335 378 343Q372 371 358 385T334 402T308 404Q263 404 229 370Q202 343 195 315T187 232V168V108Q187 78 188 68T191 55T200 49Q221 46 249 46H265V0H257L234 1Q210 2 183 2T145 3Q42 3 33 0H25V46H41Z” transform=“translate(838,0)”></path></g><g data-mml-node=“mi” transform=“translate(3610.2,0)”><path data-c=“1D6FC” d=“M34 156Q34 270 120 356T309 442Q379 442 421 402T478 304Q484 275 485 237V208Q534 282 560 374Q564 388 566 390T582 393Q603 393 603 385Q603 376 594 346T558 261T497 161L486 147L487 123Q489 67 495 47T514 26Q528 28 540 37T557 60Q559 67 562 68T577 70Q597 70 597 62Q597 56 591 43Q579 19 556 5T512 -10H505Q438 -10 414 62L411 69L400 61Q390 53 370 41T325 18T267 -2T203 -11Q124 -11 79 39T34 156ZM208 26Q257 26 306 47T379 90L403 112Q401 255 396 290Q382 405 304 405Q235 405 183 332Q156 292 139 224T121 120Q121 71 146 49T208 26Z”></path></g><g data-mml-node=“mi” transform=“translate(4416.9,0)”><path data-c=“63” d=“M370 305T349 305T313 320T297 358Q297 381 312 396Q317 401 317 402T307 404Q281 408 258 408Q209 408 178 376Q131 329 131 219Q131 137 162 90Q203 29 272 29Q313 29 338 55T374 117Q376 125 379 127T395 129H409Q415 123 415 120Q415 116 411 104T395 71T366 33T318 2T249 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transform=“translate(944,0)”></path></g><g data-mml-node=“mo” transform=“translate(5754.9,0)”><path data-c=“2061” d=””></path></g><g data-mml-node=“mi” transform=“translate(5921.6,0)”><path data-c=“1D6FD” d=“M29 -194Q23 -188 23 -186Q23 -183 102 134T186 465Q208 533 243 584T309 658Q365 705 429 705H431Q493 705 533 667T573 570Q573 465 469 396L482 383Q533 332 533 252Q533 139 448 65T257 -10Q227 -10 203 -2T165 17T143 40T131 59T126 65L62 -188Q60 -194 42 -194H29ZM353 431Q392 431 427 419L432 422Q436 426 439 429T449 439T461 453T472 471T484 495T493 524T501 560Q503 569 503 593Q503 611 502 616Q487 667 426 667Q384 667 347 643T286 582T247 514T224 455Q219 439 186 308T152 168Q151 163 151 147Q151 99 173 68Q204 26 260 26Q302 26 349 51T425 137Q441 171 449 214T457 279Q457 337 422 372Q380 358 347 358H337Q258 358 258 389Q258 396 261 403Q275 431 353 431Z”></path></g></g></g></svg></mjx-container></span></div>
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Calcule a integral dupla sobre a região indicada: , em que R é definido por: 1 <= x <= 2 e 0 <= y <= 1
Calcule a integral dupla sobre a região indicada: , em que R é definido por: 0 <= x <= pi e