Pretende-se estender um cabo de uma usina de força à margem de um rio de 900 m de largura até uma fábrica situada do outro lado do rio, 3000 m rio abaixo. O custo para estender um cabo pelo rio é de R o metro, enquanto que para estendê-lo por terra custa o metro, enquanto que para estendê-lo por terra custa o metro. Qual é o percurso mais econômico para o cabo?
4,00

Passo 1

Beleza, vamos dar uma olhada no que o exercício está pedindo. A gente precisa ajudar a encontrar o caminho mais barato para estender um cabo da usina até a fábrica, que está do outro lado do rio. O rio tem 900 metros de largura e a fábrica está 3.000 metros rio abaixo. Temos dois custos: por metro dentro do rio e por metro na terra. Vamos precisar usar um pouco de cálculo para minimizar esse custo total e descobrir qual é o melhor caminho para o cabo.

Passo 2

Primeiro, vamos entender a função de custo que foi dada:
y = sen(x^2)
Aqui, x representa a distância ao longo do rio onde o cabo sai da água e vai para a terra. A primeira parte, y = sen(x^2), calcula o custo de estender o cabo pelo rio, que forma um triângulo retângulo com 900 metros de largura. A segunda parte, , é o custo de estender o cabo por terra até a fábrica.

Passo 3

Para encontrar o valor de x que minimiza o custo total, vamos derivar a função c(x) em relação a x e igualar a derivada a zero. Isso porque o ponto mínimo ocorre onde a inclinação da função é zero.
Primeiro, vamos derivar cada parte:
  1. Derivada de :
Usamos a regra da cadeia. A derivada de é .
Então:
y = sen(x^2)
  1. Derivada de y = sen(x^2):

Passo 4

Agora, colocamos tudo junto para obter a derivada total da função custo:
y = sen(x^2)
Para encontrar o mínimo, igualamos a derivada a zero:
y = sen(x^2)

Passo 5

Vamos resolver essa equação para x:
y = sen(x^2)
Multiplicando ambos os lados por y = sen(x^2):
Agora, vamos elevar ambos os lados ao quadrado para eliminar a raiz:
y = sen(x^2)
Simplificando:
y = sen(x^2)
Subtraindo y = sen(x^2) de ambos os lados:
y = sen(x^2)
Dividindo ambos os lados por 9:
y = sen(x^2)
Simplificando:
y = sen(x^2)
Tirando a raiz quadrada de ambos os lados:

Passo 6

Agora que encontramos que x = 1200 metros, vamos verificar qual é o custo mínimo substituindo esse valor na função c(x):
y = sen(x^2)
Calculando as partes:
  1. y = sen(x^2)
Agora, multiplicando pelos custos:

Resposta

O percurso mais econômico para estender o cabo é sair da água a 1.200 metros rio abaixo, resultando em um custo total de R$ 14.700,00.

Exercícios relacionados

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<html><head></head><body><div>Deseja-se confeccionar uma trave para um campo de futebol, utilizando uma viga de <span class=“math-inline “>
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<html><head></head><body><div>Estude o sinal de cada uma das expressões abaixo: <span class="math-inline ">
<mjx-container class=“MathJax” jax=“SVG”><svg style=“vertical-align: -0.791ex;” xmlns=“
http://www.w3.org/2000/svg” width=“10.91ex” height=“2.713ex” role=“img” focusable=“false” viewBox=“0 -849.5 4822.2 1199”><title>x^6 (x^2 + 3)</title><g stroke=“currentColor” fill=“currentColor” stroke-width=“0” transform=“scale(1,-1)”><g data-mml-node=“math”><g data-mml-node=“msup”><g data-mml-node=“mi”><path data-c=“1D465” d=“M52 289Q59 331 106 386T222 442Q257 442 286 424T329 379Q371 442 430 442Q467 442 494 420T522 361Q522 332 508 314T481 292T458 288Q439 288 427 299T415 328Q415 374 465 391Q454 404 425 404Q412 404 406 402Q368 386 350 336Q290 115 290 78Q290 50 306 38T341 26Q378 26 414 59T463 140Q466 150 469 151T485 153H489Q504 153 504 145Q504 144 502 134Q486 77 440 33T333 -11Q263 -11 227 52Q186 -10 133 -10H127Q78 -10 57 16T35 71Q35 103 54 123T99 143Q142 143 142 101Q142 81 130 66T107 46T94 41L91 40Q91 39 97 36T113 29T132 26Q168 26 194 71Q203 87 217 139T245 247T261 313Q266 340 266 352Q266 380 251 392T217 404Q177 404 142 372T93 290Q91 281 88 280T72 278H58Q52 284 52 289Z”></path></g><g data-mml-node=“TeXAtom” transform=“translate(605,363) scale(0.707)” data-mjx-texclass=“ORD”><g data-mml-node=“mn”><path data-c=“36” d=“M42 313Q42 476 123 571T303 666Q372 666 402 630T432 550Q432 525 418 510T379 495Q356 495 341 509T326 548Q326 592 373 601Q351 623 311 626Q240 626 194 566Q147 500 147 364L148 360Q153 366 156 373Q197 433 263 433H267Q313 433 348 414Q372 400 396 374T435 317Q456 268 456 210V192Q456 169 451 149Q440 90 387 34T253 -22Q225 -22 199 -14T143 16T92 75T56 172T42 313ZM257 397Q227 397 205 380T171 335T154 278T148 216Q148 133 160 97T198 39Q222 21 251 21Q302 21 329 59Q342 77 347 104T352 209Q352 289 347 316T329 361Q302 397 257 397Z”></path></g></g></g><g data-mml-node=“mrow” transform=“translate(1175.2,0)”><g data-mml-node=“mo” transform=“translate(0 -0.5)”><path data-c=“28” d=“M152 251Q152 646 388 850H416Q422 844 422 841Q422 837 403 816T357 753T302 649T255 482T236 250Q236 124 255 19T301 -147T356 -251T403 -315T422 -340Q422 -343 416 -349H388Q359 -325 332 -296T271 -213T212 -97T170 56T152 251Z”></path></g><g data-mml-node=“msup” transform=“translate(458,0)”><g data-mml-node=“mi”><path data-c=“1D465” d=“M52 289Q59 331 106 386T222 442Q257 442 286 424T329 379Q371 442 430 442Q467 442 494 420T522 361Q522 332 508 314T481 292T458 288Q439 288 427 299T415 328Q415 374 465 391Q454 404 425 404Q412 404 406 402Q368 386 350 336Q290 115 290 78Q290 50 306 38T341 26Q378 26 414 59T463 140Q466 150 469 151T485 153H489Q504 153 504 145Q504 144 502 134Q486 77 440 33T333 -11Q263 -11 227 52Q186 -10 133 -10H127Q78 -10 57 16T35 71Q35 103 54 123T99 143Q142 143 142 101Q142 81 130 66T107 46T94 41L91 40Q91 39 97 36T113 29T132 26Q168 26 194 71Q203 87 217 139T245 247T261 313Q266 340 266 352Q266 380 251 392T217 404Q177 404 142 372T93 290Q91 281 88 280T72 278H58Q52 284 52 289Z”></path></g><g data-mml-node=“TeXAtom” transform=“translate(605,363) scale(0.707)” data-mjx-texclass=“ORD”><g data-mml-node=“mn”><path data-c=“32” d=“M109 429Q82 429 66 447T50 491Q50 562 103 614T235 666Q326 666 387 610T449 465Q449 422 429 383T381 315T301 241Q265 210 201 149L142 93L218 92Q375 92 385 97Q392 99 409 186V189H449V186Q448 183 436 95T421 3V0H50V19V31Q50 38 56 46T86 81Q115 113 136 137Q145 147 170 174T204 211T233 244T261 278T284 308T305 340T320 369T333 401T340 431T343 464Q343 527 309 573T212 619Q179 619 154 602T119 569T109 550Q109 549 114 549Q132 549 151 535T170 489Q170 464 154 447T109 429Z”></path></g></g></g><g data-mml-node=“mo” transform=“translate(1688.8,0)”><path data-c=“2B” d=“M56 237T56 250T70 270H369V420L370 570Q380 583 389 583Q402 583 409 568V270H707Q722 262 722 250T707 230H409V-68Q401 -82 391 -82H389H387Q375 -82 369 -68V230H70Q56 237 56 250Z”></path></g><g data-mml-node=“mn” transform=“translate(2689,0)”><path data-c=“33” d=“M127 463Q100 463 85 480T69 524Q69 579 117 622T233 665Q268 665 277 664Q351 652 390 611T430 522Q430 470 396 421T302 350L299 348Q299 347 308 345T337 336T375 315Q457 262 457 175Q457 96 395 37T238 -22Q158 -22 100 21T42 130Q42 158 60 175T105 193Q133 193 151 175T169 130Q169 119 166 110T159 94T148 82T136 74T126 70T118 67L114 66Q165 21 238 21Q293 21 321 74Q338 107 338 175V195Q338 290 274 322Q259 328 213 329L171 330L168 332Q166 335 166 348Q166 366 174 366Q202 366 232 371Q266 376 294 413T322 525V533Q322 590 287 612Q265 626 240 626Q208 626 181 615T143 592T132 580H135Q138 579 143 578T153 573T165 566T175 555T183 540T186 520Q186 498 172 481T127 463Z”></path></g><g data-mml-node=“mo” transform=“translate(3189,0) translate(0 -0.5)”><path data-c=“29” d=“M305 251Q305 -145 69 -349H56Q43 -349 39 -347T35 -338Q37 -333 60 -307T108 -239T160 -136T204 27T221 250T204 473T160 636T108 740T60 807T35 839Q35 850 50 850H56H69Q197 743 256 566Q305 425 305 251Z”></path></g></g></g></g></svg></mjx-container></span></div>
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<html><head></head><body><div>Estude o sinal de cada uma das expressões abaixo: <span class="math-inline ">
<mjx-container class=“MathJax” jax=“SVG”><svg style=“vertical-align: -0.566ex;” xmlns=“
http://www.w3.org/2000/svg” width=“15.034ex” height=“2.262ex” role=“img” focusable=“false” viewBox=“0 -750 6644.9 1000”><title>(2 x + 1)(x - 2)</title><g stroke=“currentColor” fill=“currentColor” stroke-width=“0” transform=“scale(1,-1)”><g data-mml-node=“math”><g data-mml-node=“mo”><path data-c=“28” d=“M94 250Q94 319 104 381T127 488T164 576T202 643T244 695T277 729T302 750H315H319Q333 750 333 741Q333 738 316 720T275 667T226 581T184 443T167 250T184 58T225 -81T274 -167T316 -220T333 -241Q333 -250 318 -250H315H302L274 -226Q180 -141 137 -14T94 250Z”></path></g><g data-mml-node=“mn” transform=“translate(389,0)”><path data-c=“32” d=“M109 429Q82 429 66 447T50 491Q50 562 103 614T235 666Q326 666 387 610T449 465Q449 422 429 383T381 315T301 241Q265 210 201 149L142 93L218 92Q375 92 385 97Q392 99 409 186V189H449V186Q448 183 436 95T421 3V0H50V19V31Q50 38 56 46T86 81Q115 113 136 137Q145 147 170 174T204 211T233 244T261 278T284 308T305 340T320 369T333 401T340 431T343 464Q343 527 309 573T212 619Q179 619 154 602T119 569T109 550Q109 549 114 549Q132 549 151 535T170 489Q170 464 154 447T109 429Z”></path></g><g data-mml-node=“mi” transform=“translate(889,0)”><path data-c=“1D465” d=“M52 289Q59 331 106 386T222 442Q257 442 286 424T329 379Q371 442 430 442Q467 442 494 420T522 361Q522 332 508 314T481 292T458 288Q439 288 427 299T415 328Q415 374 465 391Q454 404 425 404Q412 404 406 402Q368 386 350 336Q290 115 290 78Q290 50 306 38T341 26Q378 26 414 59T463 140Q466 150 469 151T485 153H489Q504 153 504 145Q504 144 502 134Q486 77 440 33T333 -11Q263 -11 227 52Q186 -10 133 -10H127Q78 -10 57 16T35 71Q35 103 54 123T99 143Q142 143 142 101Q142 81 130 66T107 46T94 41L91 40Q91 39 97 36T113 29T132 26Q168 26 194 71Q203 87 217 139T245 247T261 313Q266 340 266 352Q266 380 251 392T217 404Q177 404 142 372T93 290Q91 281 88 280T72 278H58Q52 284 52 289Z”></path></g><g data-mml-node=“mo” transform=“translate(1683.2,0)”><path data-c=“2B” d=“M56 237T56 250T70 270H369V420L370 570Q380 583 389 583Q402 583 409 568V270H707Q722 262 722 250T707 230H409V-68Q401 -82 391 -82H389H387Q375 -82 369 -68V230H70Q56 237 56 250Z”></path></g><g data-mml-node=“mn” transform=“translate(2683.4,0)”><path data-c=“31” d=“M213 578L200 573Q186 568 160 563T102 556H83V602H102Q149 604 189 617T245 641T273 663Q275 666 285 666Q294 666 302 660V361L303 61Q310 54 315 52T339 48T401 46H427V0H416Q395 3 257 3Q121 3 100 0H88V46H114Q136 46 152 46T177 47T193 50T201 52T207 57T213 61V578Z”></path></g><g data-mml-node=“mo” transform=“translate(3183.4,0)”><path data-c=“29” d=“M60 749L64 750Q69 750 74 750H86L114 726Q208 641 251 514T294 250Q294 182 284 119T261 12T224 -76T186 -143T145 -194T113 -227T90 -246Q87 -249 86 -250H74Q66 -250 63 -250T58 -247T55 -238Q56 -237 66 -225Q221 -64 221 250T66 725Q56 737 55 738Q55 746 60 749Z”></path></g><g data-mml-node=“mo” transform=“translate(3572.4,0)”><path data-c=“28” d=“M94 250Q94 319 104 381T127 488T164 576T202 643T244 695T277 729T302 750H315H319Q333 750 333 741Q333 738 316 720T275 667T226 581T184 443T167 250T184 58T225 -81T274 -167T316 -220T333 -241Q333 -250 318 -250H315H302L274 -226Q180 -141 137 -14T94 250Z”></path></g><g data-mml-node=“mi” transform=“translate(3961.4,0)”><path data-c=“1D465” d=“M52 289Q59 331 106 386T222 442Q257 442 286 424T329 379Q371 442 430 442Q467 442 494 420T522 361Q522 332 508 314T481 292T458 288Q439 288 427 299T415 328Q415 374 465 391Q454 404 425 404Q412 404 406 402Q368 386 350 336Q290 115 290 78Q290 50 306 38T341 26Q378 26 414 59T463 140Q466 150 469 151T485 153H489Q504 153 504 145Q504 144 502 134Q486 77 440 33T333 -11Q263 -11 227 52Q186 -10 133 -10H127Q78 -10 57 16T35 71Q35 103 54 123T99 143Q142 143 142 101Q142 81 130 66T107 46T94 41L91 40Q91 39 97 36T113 29T132 26Q168 26 194 71Q203 87 217 139T245 247T261 313Q266 340 266 352Q266 380 251 392T217 404Q177 404 142 372T93 290Q91 281 88 280T72 278H58Q52 284 52 289Z”></path></g><g data-mml-node=“mo” transform=“translate(4755.7,0)”><path data-c=“2212” d=“M84 237T84 250T98 270H679Q694 262 694 250T679 230H98Q84 237 84 250Z”></path></g><g data-mml-node=“mn” transform=“translate(5755.9,0)”><path data-c=“32” d=“M109 429Q82 429 66 447T50 491Q50 562 103 614T235 666Q326 666 387 610T449 465Q449 422 429 383T381 315T301 241Q265 210 201 149L142 93L218 92Q375 92 385 97Q392 99 409 186V189H449V186Q448 183 436 95T421 3V0H50V19V31Q50 38 56 46T86 81Q115 113 136 137Q145 147 170 174T204 211T233 244T261 278T284 308T305 340T320 369T333 401T340 431T343 464Q343 527 309 573T212 619Q179 619 154 602T119 569T109 550Q109 549 114 549Q132 549 151 535T170 489Q170 464 154 447T109 429Z”></path></g><g data-mml-node=“mo” transform=“translate(6255.9,0)”><path data-c=“29” d=“M60 749L64 750Q69 750 74 750H86L114 726Q208 641 251 514T294 250Q294 182 284 119T261 12T224 -76T186 -143T145 -194T113 -227T90 -246Q87 -249 86 -250H74Q66 -250 63 -250T58 -247T55 -238Q56 -237 66 -225Q221 -64 221 250T66 725Q56 737 55 738Q55 746 60 749Z”></path></g></g></g></svg></mjx-container></span></div>
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