Enunciado

The U-tube in Fig. P2.140 is moving to the right with variable velocity. The water level in the left tube is 6 cm, and

the level in the right tube is 16 cm. Determine the acceleration and its direction.

Passo 1

Saaaalve, tranquilo? Vamos lá resolver mais uma questão juntos?! 😊

Uma vez que o movimento é horizontal. Escreva a relação para calcular a aceleração da água no tubo.

a x g = h 1 - h 2 h . . . ( 1 )

Aqui, é a aceleração horizontal da água no a x tubo, é a g aceleração devido à gravidade, é a altura do nível da água no lado h 1 esquerdo, é a altura do nível h 2 da água no lado direito e é a h distância horizontal.

a x g   = h 1 - h 2 h a x 9.81   m / s 2 = 6   c m - 16   c m 20   c m a x   = - 0.5 × 9.81   m / s 2   = - 4.905   m / s 2

Assim, a aceleração da água no tubo é 4.905   m / s 2 .

Passo 2

Aqui, sinal negativo indica a desaceleração. Assim, o tubo está desacelerando à medida que se move para a direita.

Resposta

a x = 4.905   m / s 2

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